From d13605500dac2e1e6aa53dd7494af8e209acbd26 Mon Sep 17 00:00:00 2001
From: xianliticn <mitochondriacn@gmail.com>
Date: Thu, 16 Apr 2026 21:22:20 +0800
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---
 content/blog/使用归纳法证明二项式定理.md | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/content/blog/使用归纳法证明二项式定理.md b/content/blog/使用归纳法证明二项式定理.md
index f6e2b1f..e825cc6 100644
--- a/content/blog/使用归纳法证明二项式定理.md
+++ b/content/blog/使用归纳法证明二项式定理.md
@@ -22,14 +22,14 @@ $$
 试图使左右两边相等，需要使得左边分母为$k!(n+1-k)!$，所以通分得：
 
 $$
-\begin{align}
+\begin{align*}
 & \frac{n!}{(k-1)!(n-k+1)!} + \frac{n!}{k!(n-k)!} \\\\
 &= \frac{n!k}{k!(n-k+1)!} + \frac{n!(n-k+1)}{k!(n-k+1)!} \\\\
 &= \frac{n!k+n!(n-k+1)}{k!(n-k+1)!} \\\\
 &= \frac{n!(n+1)}{k!(n-k+1)!} \\\\
 &= \frac{(n+1)!}{k!(n+1-k)!} \\\\
 &= \binom{n+1}{k}. \tag*{$\blacksquare$}
-\end{align}
+\end{align*}
 $$
 
 随后证明二项式定理