diff --git a/content/blog/使用归纳法证明二项式定理.md b/content/blog/使用归纳法证明二项式定理.md
index a647cf2..3b962b0 100644
--- a/content/blog/使用归纳法证明二项式定理.md
+++ b/content/blog/使用归纳法证明二项式定理.md
@@ -23,7 +23,7 @@ $$
 
 $$
 \begin{aligned}
-& \frac{n!}{(k-1)!(n-k+1)!} + \frac{n!}{k!(n-k)!} \\
+& \frac{n!}{(k-1)!(n-k+1)!} + \frac{n!}{k!(n-k)!} \\\\
 &= \frac{n!k}{k!(n-k+1)!} + \frac{n!(n-k+1)}{k!(n-k+1)!} \\
 &= \frac{n!k+n!(n-k+1)}{k!(n-k+1)!} \\
 &= \frac{n!(n+1)}{k!(n-k+1)!} \\
@@ -44,7 +44,7 @@ $$(a+b)^0 = 1 = \sum_{k=0}^{0}\binom{0}{k}a^{0-k}b^k = a^0b^0.$$
 
 $$
 \begin{aligned}
-&= (a+b)^{n+1} \\
+& (a+b)^{n+1} \\
 &= (a+b)(a+b)^n \\
 &= (a+b) \sum_{k=0}^{n} \binom{n}{k} a^{n-k}b^k \\
 &= \sum_{k=0}^{n} \binom{n}{k} (a^{n+1-k}b^k + a^{n-k}b^{k+1}) \\